0=13x^2+2x

Solution for 0=13x^2+2x equation:

0=13x^2+2x

We move all terms to the left:

0-(13x^2+2x)=0

We add all the numbers together, and all the variables

-(13x^2+2x)=0

We get rid of parentheses

-13x^2-2x=0

a = -13; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-13)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-13}=\frac{0}{-26}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-13}=\frac{4}{-26}
=-2/13
$